The equation of the asymptotes of the hyperbola 2x2+5xy+2y2−11x–7y–4=0, is
A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Equation of hyperbola is 2x2+5xy+2y2−11x−7y−4=0 …… (i) Let asymptotes of the hyperbola (i) be 2x2+5xy+2y2−11x−7y+c=0 …… (ii) Since, equation (ii) represents a pair of lines. ∴∣∣
∣
∣∣25/2−11/25/22−7/2−11/2−7/2c∣∣
∣
∣∣=0 ⇒−112(−354+11)+72(−7+554)+c(4−254)=0⇒94c=−998+1898=908⇒c=5∴ Equation of the required asymptotes is 2x2+5xy+2y2−11x−7y+5=0