wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the asymptotes of the hyperbola 2x2+5xy+2y211x7y4=0, is

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C
Equation of hyperbola is
2x2+5xy+2y211x7y4=0 …… (i)
Let asymptotes of the hyperbola (i) be
2x2+5xy+2y211x7y+c=0 …… (ii)
Since, equation (ii) represents a pair of lines.
∣ ∣ ∣25/211/25/227/211/27/2c∣ ∣ ∣=0
112(354+11)+72(7+554)+c(4254)=0 94c=998+1898=908c=5
Equation of the required asymptotes is
2x2+5xy+2y211x7y+5=0

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon