wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the auxiliary circle of the hyperbola x264y236=1 is

A
x2+y2=100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2+y2=28
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+y2=64
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x2+y2=36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x2+y2=64
For any hyperbola of the form
x2a2y2b2=1,
the auxiliary circle is x2+y2=a2
Now for hyperbolax264y236=1,a=8 and b=6
Thus the auxiliary circle is x2+y2=64

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon