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Area of a Triangle

The equation ...

Question

The equation of the axis of the parabola whose focus is $(0, 0)$ and directrix is $5 x - 4 y + 5 = 0$ , will be

5 x - 4 y = 0

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4 x + 5 y = 0

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4 x - 5 y = 0

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none

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Solution

The correct option is B $4 x + 5 y = 0$
Slope of directrix $= 5 / 4$
$∴$ Slpoe of axis $= - 4 / 5$
equation $\Rightarrow \frac{y - 0}{x - 0} = \frac{- 4}{5}$
$5 y + 4 x = 0$

Suggest Corrections

Similar questions

(5, 3)

3 x - 4 y + 1 = 0

(0, 0)

x - y + 1 = 0

y^{2} + 4 x + 4 y - 3 = 0

A = (5, 0)

B = (0, 4)

P

| P A |^{2} - | P B |^{2} = 9

(2, 5)

y = 3

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