The equation of the bisector of the angle between the lines $3 x - 4 y + 7 = 0$ and $12 x + 5 y - 2 = 0$

11 x + 3 y - 9 = 0

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3 x - 11 y + 9 = 0

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11 x - 3 y - 9 = 0

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11 x - 3 y + 9 = 0

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Solution

The correct option is D $11 x - 3 y + 9 = 0$
Equation of angle bisectors sre
$\frac{3 x - 4 y + 7}{\sqrt{9 + 16}} = \pm \frac{12 x + 5 y - 2}{\sqrt{144 + 25}} \frac{3 x - 4 y + 7}{5} = \pm \frac{12 x + 5 y - 2}{13} 39 x - 52 y + 91 = \pm (60 x + 25 y - 10) 39 x - 52 y + 91 = 60 x + 25 y - 10 21 x + 77 y + 101 = 0........... (i) 39 x - 52 y + 91 = - 60 x - 25 y + 10 99 x - 27 y + 81 = 0 11 x - 3 y + 9 = 0.......... (i i)$

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Similar questions

3 x^{2} + 10 x y + 3 y^{2} - 2 x + 2 y - 1 = 0

3 x^{2} + 10 x y + 3 y^{2} - 11 x + 7 y - 20 = 0

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x^{2} - y^{2} = 0

3 x + 5 y = 19

(3, 2)

3 x - 4 y + 7 = 0

12 x + 5 y - 2 = 0

3 x + 4 y + 6 = 0, 6 x + 5 y + 9 = 0

3 x + 3 y + 5 = 0

3 x + 4 y + 5 = 0

12 x - 5 y - 7 = 0

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