wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the chord joining two points (x1,y1) and (x2,y2) on the rectangular hyperbola xy=c2 is

A
xx1+x2+yy1+y2=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
xx1x2+yy1y2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
xy1+y2+yx1+x2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
xy1y2+yx1x2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A xx1+x2+yy1+y2=1
The midpoint of the chord is (x1+x22,y1+y22)
The equation of the chord in terms of its midpoint is
T=S1
x2(y1+y22)+y2(x1+x22)c2=(x1+x22)(y1+y22)c2
x(y1+y2)+y(x1+x2)=(x1+x2)(y1+y2)
xx1+x2+yy1+y2=1

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon