The equation of the chord of the circle $x^{2} + y^{2} - 4 x = 0$ whose mid point is $(1, 0)$ is

y = 2

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y = 1

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x = 2

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x = 1.

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Solution

The correct option is D $x = 1.$
The equation of the chord is
$x \times 1 + 0 \times y - 2 (x + 1) = 1 + 0 - 4$ [ Using $T = S_{1}$ ]
$\Rightarrow - x - 2 = - 3 \Rightarrow x = 1$

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