The equation of the circle concentric with the circle $x^{2} + y^{2} + 8 x + 10 y - 7 = 0$ and passing through the centre of the circle $x^{2} + y^{2} - 4 x - 6 y = 0$ is

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Solution

The correct option is B
Centre is (-4, -5) and passes through (2, 3), then the equation of the circle is $x^{2} + y^{2} + 8 x + 10 y - 59 = 0$ .

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Similar questions

x^{2} + y^{2} + 8 x + 10 y - 7 = 0

x^{2} + y^{2} - 4 x - 6 y = 0

x^{2} + y^{2} - 8 x + 6 y - 5 = 0

(- 2, - 7)

x^{2} + y^{2} - 8 x + 6 y + 21 = 0

x^{2} + y^{2} + 4 x - 10 y - 115 = 0

x^{2} + y^{2} - 4 x - 6 y - 12 = 0, x^{2} + y^{2} + 6 x - 2 y + 1 = 0

The equation of the circle which passes through the points (2, 3) and (4, 5) and the centre lies on the straight line y – 4x + 3 = 0, is

x^{2} + y^{2} - 6 x - 4 y - 11 = 0

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