Question

The equation of the circle in the first quadrature touching each coordinate axis at a distance of one unit from the origin

• A. $x^2+y^2-2x-2y+1=0$
• B. $x^2+y^2-2x-1=0$
• C. $x^2+y^2-2x=0$
• D. None of these

Answer 1

The correct option is A $x^2+y^2-2x-2y+1=0$

We can clearly see from diagram that co-ordinates of centre of circle $=(1,1)$ & radius is unit

Thus equation of circle:-

$(x-1{)}^2+(y-1{)}^2=1^2$

$x^2+y^2-2x-2y+1=0$