wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the circle passing through (4,6) and having centre (1,2) is

A
x2+y22x4y20=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+y22x+4y20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+y2+2x4y20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y2+2x+4y20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x2+y22x4y20=0
Let coordinates of point A are (4,6)
As circle is passing through point A, point A lies on circle.

Let center of circle is C(1,2)
h=1 and k=2

Thus, AC is radius of circle.

By distance formula,
AC=r=(41)2+(62)2

r=(3)2+(4)2

r=9+16

r=25

r=5

Thus, equation of circle is,
(xh)2+(yk)2=r2

(x1)2+(y2)2=(5)2

x22x+1+y24y+4=25

x2+y22x4y20=0

Thus, answer is option (A)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon