wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the circle passing through the foci of the ellipse x216+y29=1, and having centre at (0,3) is

A
x2+y26y7=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+y26y+7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+y26y5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y26y+5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x2+y26y7=0
The equation of the ellipse is
x216+y29=1
So, c=±a2b2
=169
c=±7

radius of circle, r=OF
=(30)2+(07)2
=4
Equation of circle having centre (0,3) and radius 4 is
(x0)2+(y3)2=42
x2+y26y7=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon