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Question

The equation of the circle passing through the point (2,1) and touching y-axis at the origin is

A
x2+y25x=0
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B
2x2+2y25x=0
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C
x2+y2+5x=0
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D
x2y25x=0
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Solution

The correct option is B 2x2+2y25x=0
Let the equation of required circle is x2+y2+2gx+2fy+c=0
It passes through origin c=0
it touches yaxisf2=cf=0
It passes through (2,1)22+12+2g(2)+2(0)(2)+0=04g=5g=54
Substituing the values of g,f,c
The equation is 2x2+2y25x=0

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