The equation of the circle touching the y−axis whose radius is 5 units and y−coordinate of the centre is −7, is
A
x2+y2−10x+14y+49=0
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B
x2+y2+10x+14y+49=0
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C
x2+y2+10x+14y+25=0
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D
x2+y2−10x+14y+25=0
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Solution
The correct options are Ax2+y2−10x+14y+49=0 Bx2+y2+10x+14y+49=0 Given : Circle touches the y−axis and the radius is 5 units, so the centre of the circle is C=(±5,−7) So, the equation of the circle is (x±5)2+(y+7)2=52 ⇒x2+y2−10x+14y+49=0 And x2+y2+10x+14y+49=0