The equation of the circle which touches both the axes and the line x3-y4-1 and lies in the first quadrant is x-c2-y-c2-c2 where c is

After comparing this (x c) #178;+(y c) #178;=c #178;we will get c=6 ...

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Standard XII

Mathematics

Definition of Circle

The equation ...

Question

The equation of the circle which touches both the axes and the line $\frac{x}{3} + \frac{y}{4} = 1$ and lies in the first quadrant is $(x - c)^{2} + (y - c)^{2} = c^{2}$ where $c$ is

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Solution

After comparing this (x-c)²+(y-c)²=c²
we will get c=6

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The equation of the circle which touches both the axes and the line x3+y4=1 and lies in the first quadrant is (x−c)2+(y−c)2=c2 where c is

After comparing this (x-c)²+(y-c)²=c²we will get c=6

The equation of the circle which touches both the axes and the line $\frac{x}{3} + \frac{y}{4} = 1$ and lies in the first quadrant is $(x - c)^{2} + (y - c)^{2} = c^{2}$ where $c$ is

After comparing this (x-c)²+(y-c)²=c²
we will get c=6