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Question

The equation of the circle which touches the axis of y at the origin and passes through (3,4) is-

A
4(x2+y2)25x=0
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B
3(x2+y2)25x=0
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C
2(x2+y2)3x=0
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D
4(x2+y2)25x+10=0
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Solution

The correct option is B 3(x2+y2)25x=0
The center of the circle lies on the x-axis
Let a be the radius of the circle, then coordinate of the center are (a,0)

The circle passes through (3,4) , therefore

(a3)2+(04)2=a6a+25=0a=256

So, the equation of the circle is

(xa)2+(y0)2=a2

x2+y22ax=0

3(x2+y2)25x=0

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