Question

The equation of the circle whose radius is 5 and which touches the circle $x^2+y^2-2x-4y-20=0$ externally at the point (5, 5), is

• A. $x^2+y^2-18x-16y-120=0$
• B. $x^2+y^2-18x-16y+120=0$
• C. $x^2+y^2+18x+16y-120=0$
• D. $x^2+y^2+18x-16y+120=0$

Answer 1

The correct option is B $x^2+y^2-18x-16y+120=0$

Let the centre of the required circle be $(x_1,y_1)$ and the centre of given circle is (1, 2). Since radii of both circles are same, therefore, point of contact (5, 5) is the mid point of the line joining the centres of both circles. Hence $x_1=9$ and $y_1=8.$ Hence the required equation is $(x-9{)}^2+(y-8{)}^2=25$

$\Rightarrow x^2+y^2-18x-16y+120=0.$