The equation of the circle with center -a-b and radius -a2-b2 is-A- x-a2-y-b2-a2-b2B- x-a2-y-b2-a2-b2C- x-a2-y-b2-a2-b2D- x-a2-y-b2-a2-b2

The correct option is C (x + a)2 + (y + b)2 = a2 – b2 The equation of required circle is: (x + a)2 + (y + b)2 = a2 – b2 ...

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Equation of Circle with (h,k) as Center

The equation ...

Question

The equation of the circle with center (– a, – b) and radius √a² – b² is:

(x – a)² + (y – b)² = √a² – b²

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(x – a)²+ (y + b)²= a² + b²

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(x + a)² + (y + b)² = a² – b²

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(x – a)² + (y – b)² = a² – b²

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The length of common chord of the circles $(x - a)^{2} + y^{2}$ = $a^{2}$ and $x^{2} + (y - b)^{2}$ = $b^{2}$ is

The length of the chord intercepted by the circle $x^{2} + y^{2} = r^{2}$ on the line $\frac{x}{a} + \frac{y}{b} = 1$

Simplify:
${(a - b)}^{2} + 4 a b$

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

(a,b) is the mid point of the chord $¯ A B$ of the circle $x^{2} + y^{2} = r^{2}$ . The tangent at A,B meet a C. then area of $Δ A B C$

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