The equation of the circumcircle of the quadrilateral formed by the four lines $x + y \pm 1 = 0$ and $x - y \pm 1 = 0$ is:

x^{2} + y^{2} = 4

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x^{2} + y^{2} = 2

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x^{2} + y^{2} = 1

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x^{2} + y^{2} = 3

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Solution

The correct option is D $x^{2} + y^{2} = 1$
So, $e q^{n}$ of circumcircle of quadrilateral ABC D has
centre of (0,0) and radius 1,
So, $x^{2} + y^{2} = 1$

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The equation of the circumcircle of the quadrilateral formed by the four lines x+y±1=0 and x−y±1=0 is:

The correct option is D x2+y2=1So, eqn of circumcircle of quadrilateral ABC D hascentre of (0,0) and radius 1,So, x2+y2=1

The equation of the circumcircle of the quadrilateral formed by the four lines $x + y \pm 1 = 0$ and $x - y \pm 1 = 0$ is:

The correct option is D $x^{2} + y^{2} = 1$
So, $e q^{n}$ of circumcircle of quadrilateral ABC D has
centre of (0,0) and radius 1,
So, $x^{2} + y^{2} = 1$