The equation of the circumcircle of the triangle formed by the lines x = 0, y = 0, 2x + 3y = 5 is
Since circle is passing through (0, 0).
∴ Equation of circle will be x2+y2+2gx+2fy=0 ...(i)
Also, circle is passing through (5/2, 0) and (0, 5/3)
So, g = -5/4, f = -5/6.
Put the values of g and f in equation (i).
After solving, we get 6(x2+y2)−5(3x+2y)=0, which is the required equation of the circle.