The equation of the circumcircle of the triangle formed by the lines y -3 x -6- y -3 x -6- and y -0- is A- x2-y2-4 y-0B- x2-y2-4 x-0C- x2-y2-4 y-12D- x2-y2-4 x-12

The correct option is On Solving y =0 and y+√(3)x = 6, we get (2,√(3), 0) only one option satisfies the co ordinate. ...

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Standard IX

Mathematics

Definition of Circle

The equation ...

Question

The equation of the circumcircle of the triangle formed by the lines $y + \sqrt{3} x = 6, y - \sqrt{3} x = 6,$ and $y = 0,$ is

x^{2} + y^{2} - 4 y = 0

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x^{2} + y^{2} + 4 x = 0

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x^{2} + y^{2} - 4 y = 12

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x^{2} + y^{2} + 4 x = 12

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Solution

On Solving y =0 and $y + \sqrt{3} x = 6,$
we get $(2, \sqrt{3}, 0)$
only one option satisfies the co-ordinate.

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The equation of the circumcircle of the triangle formed by the lines y+√3x=6,y−√3x=6, and y=0, is

On Solving y =0 and y+√3x=6, we get (2,√3,0) only one option satisfies the co-ordinate.

The equation of the circumcircle of the triangle formed by the lines $y + \sqrt{3} x = 6, y - \sqrt{3} x = 6,$ and $y = 0,$ is

On Solving y =0 and $y + \sqrt{3} x = 6,$
we get $(2, \sqrt{3}, 0)$
only one option satisfies the co-ordinate.