Question

The equation of the circumcircle of the triangle formed by the lines $y+\sqrt{3}x=6,y-\sqrt{3}x=6,$ and $y=0,$ is

• A. $x^2+y^2-4y=0$
• B. $x^2+y^2+4x=0$
• C. $x^2+y^2-4y=12$
• D. $x^2+y^2+4x=12$

Answer 1

On Solving y =0 and $y+\sqrt{3}x=6,$
we get $(2,\sqrt{3},0)$
only one option satisfies the co-ordinate.