The equation of the circumcircle of the triangle formed by the lines y-3-x - 6- y - -3-x - 6- and y - 0- is x-2 - y-2 - 4x - 12x-2 - y-2 - 4x - 0x-2 - y-2 - 4y - 0x-2 - y-2 - 4y - 12

The correct option is On Solving y =0 and y+√(3)x = 6, we get (2,√(3), 0) only one option satisfies the co ordinate. ...

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Standard XII

Mathematics

Definition of Circle

The equation ...

Question

The equation of the circumcircle of the triangle formed by the lines $y + \sqrt{3} x = 6, y - \sqrt{3} x = 6,$ and $y = 0,$ is

x^{2} + y^{2} - 4 y = 0

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x^{2} + y^{2} + 4 x = 0

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x^{2} + y^{2} - 4 y = 12

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x^{2} + y^{2} + 4 x = 12

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Solution

On Solving y =0 and $y + \sqrt{3} x = 6,$
we get $(2, \sqrt{3}, 0)$
only one option satisfies the co-ordinate.

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Q. The equation of the circumcircle of the triangle formed by the lines

y + \sqrt{3} x = 6, y - \sqrt{3} x = 6,

and

y = 0,

The equation of a circle which cuts the three circles

$x^{2} + y^{2} - 3 x - 6 y + 14 = 0,$

$x^{2} + y^{2} - x - 4 y + 8 = 0$

$x^{2} + y^{2} + 2 x - 6 y + 9 = 0$

orthogonally is $- ------------- -$

Find the equation of circle circumscribing the quadrilateral formed by four lines $3 x + 4 y - 5 = 0$ , $4 x - 3 y - 5 = 0$ , $3 x + 4 y + 5 = 0$ and $4 x - 3 y + 5 = 0$

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The equation of the circumcircle of the triangle formed by the lines y+√3x=6,y−√3x=6, and y=0, is

On Solving y =0 and y+√3x=6, we get (2,√3,0) only one option satisfies the co-ordinate.

The equation of the circumcircle of the triangle formed by the lines $y + \sqrt{3} x = 6, y - \sqrt{3} x = 6,$ and $y = 0,$ is

On Solving y =0 and $y + \sqrt{3} x = 6,$
we get $(2, \sqrt{3}, 0)$
only one option satisfies the co-ordinate.