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Question

The equation of the conic with e=12 and equation of directrix rcosθ=2 is:

A
rcosθ=r+1
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B
rsinθ=2(r+1)
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C
rcosθ=2(r1)
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D
rsinθ=2(r1)
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Solution

The correct option is D rcosθ=2(r1)
Directrix of lr=1+ecosθ is lr=ecosθ
by comparing we can get , l=1
Putting these values in dielectrix equation,
1r=1+12cosθ
Therefore, equation of conic is rcosθ=2(r1)

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