wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the conic with focus at (1,-1) directrix x-y+1=0 and eccentricity2 is


A

xy=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2xy+4y4y1=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

x2y2=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2xy4x+4y+1=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

2xy4x+4y+1=0


Let (x,y)be any point on the hyperbola Then,the distance of any point from the focus is eccentricity times the distance from the directrix.

(x1)2+(y+1)2=2xy+12

Squaring both the sides, we get:

(x1)2+(y+1)2=(xy+1)2

x22x+1+y2+1+2y=x2+y2+12xy2y+2x

2xy4x+4y+1=0


flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon