Question

The equation of the conjugate axis of the hyperbola $\frac{{\left(y-2\right)}^2}{9}-\frac{{\left(x+3\right)}^2}{16}=1$

• A. $y=2$
• B. $y=6$
• C. $y=8$
• D. $y=3$

Answer 1

The correct option is A $y=2$

$\frac{{(y-2)}^2}{9}-\frac{{(x+3)}^2}{16}=1$

Conjugate axis of $\frac{{\left(y\right)}^2}{9^2}-\frac{{\left(x\right)}^2}{6^2}=1$ is $y=0$ or x axis.

then in this y is shifted bu 2 units upwards

So conjugate axis is $y=2$

A is correct