The equation of the diameter of the circle $x^{2} + y^{2} + 2 x - 4 y - 4 = 0$ which is parallel to $3 x + 5 y - 4 = 0$ is

3 x + 5 y = - 7

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3 x + 5 y = 7

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3 x + 5 y = 9

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3 x + 5 y = 1

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Solution

The correct option is B $3 x + 5 y = 7$
Let equation of diameter be
$3 x + 5 y = λ$
$∵$ It passes through centre $= (- 1, 2)$
$\Rightarrow λ = - 3 + 10 = 7$
$∴$ Diameter equation is
$3 x + 5 y = 7$

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Similar questions

x^{2} + y^{2} + 2 x - 4 y - 4 = 0

3 x + 5 y - 4 = 0

x^{2} + y^{2} + 2 x - 4 y = 4

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

3 x - 4 y - 1 = 0

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

3 x - 4 y - 1 = 0

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