The equation of the directrix of the parabola, $y^{2} + 4 y + 4 x + 2 = 0$ is -

x = - 1

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x = 1

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x = - \frac{3}{2}

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x = \frac{3}{2}

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Solution

The correct option is D $x = \frac{3}{2}$
Given equation of parabola
$y^{2} + 4 y + 4 x + 2 = 0$
or $(y + 2)^{2} + 4 x + 2 = 0$
or $(y + 2)^{2} = - 4 (x - 12)$
Its directrix is x−12=1
or x=32
Hence D is the correct answer.

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