wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the ellipse, whose length of the major axis is 20 and foci are (0,±5), is

A
x210+y253=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x225+y2100=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x275+y2100=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x210+y225=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x275+y2100=1
Since the foci are on yaxis, the major axis will be along the yaxis. So, equation of the ellipse is of the form
x2a2+y2b2=1(b>a).

Given,
Length of major axis 2b=20
b=10

and be=5
b2e2=25b2a2=25a2=75

Hence, the equation of the ellipse is
x275+y2100=1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon