The equation of the ellipse with focus (-1,1), directrix x-y+3=0 and eccentricity 1/2 is
A
7x2+2xy+7y2+10x+10y+7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7x2+7y2+2xy−10y+10x+7=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7x2+2xy+7y2+10x−10y−7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B7x2+7y2+2xy−10y+10x+7=0
Let P(x,y) be any point on the ellipse whose focus and eccentricity are S(-1,1) and e=12, respectively. Let PM be the perpendicular from P on the directrix. Then SP=e×PM ⇒SP=12×PM ⇒2SP=PM ⇒4(SP)2=PM2 4[(x+1)2+(y−1)2]=(x−y+3√12+(−1)2)2 ⇒4[(x+1+2x+y2+1−2y)]=x2+y2+9−2xy−6y+6x2 ⇒8x2+8+16x+8y2+8−16y=x2+y2+9−2xy−6y+6x ⇒7x2+7y2+2xy−10y+10x+7=0 This is the required equation of the ellipse.