The equation of the graph given below is
By looking at the graph, we can easily say that the line passes through the points (2, 0) and (0, -4).
We can identify the equation of the line passing through these points by substituting the points in the equation of the line.
By substituting x = 2, y = 0 in equation y = 2x - 4, we get
0 = 2(2) - 4 = 0
and also when x = 0, y = -4 substituted in the equation y = 2x - 4, we get -4 = 2(0) - 0 = -4
∴ The equation y = 2x - 4 is satisfied by both the points. So, equation of the line in the given graph is y = 2x - 4.
By substituting x = 2 and y = 0 in 3y = 6x - 15, 0 ≠ -3.
∴ 3y = 6x - 15 is not the equation of the line in the given graph.
Bysubstituting x = 2 and y = 0 in y - 2x = 4, -4 ≠ 4.
∴ y - 2x = 4 is not the equation of the line in the given graph.
By substituting x = 2 and y = 0 in y = 2x + 2, 0 ≠ 6.
∴ y = 2x + 2 is not the equation of the line in the given graph.