The equation of the hyperbola whose asymptotes are 3x+4y–2=0,2x+y+1=0 and which passes through the point (1, 1) is
A
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B
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C
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D
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Solution
The correct option is B Equation of pair of asymptotes is (3x+4y–2)(2x+y+1)=0⇒6x2+11xy+4y2−x+2y−2=0 ∴ Equation of the hyperbola is 6x2+11xy+4y2−x+2y+k=0 Since it passes through (1, 1) we get, 6x2+11xy+4y2−x+2y−22=0