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Question

The equation of the hyperbola whose asymptotes are 3x+4y2=0,2x+y+1=0 and which passes
through the point (1, 1) is

A
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B
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C
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D
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Solution

The correct option is B
Equation of pair of asymptotes is (3x+4y2)(2x+y+1)=06x2+11xy+4y2x+2y2=0
Equation of the hyperbola is 6x2+11xy+4y2x+2y+k=0
Since it passes through (1, 1) we get, 6x2+11xy+4y2x+2y22=0

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