The equation of the hyperbola whose centre is (5, 2), vertex is (9, 2) and the length of conjugate axis is 6 is
CA=a⇒a=4 and b=3 ∴Hyperbola is(x−5)216−(y−2)29=1
Find the equation of the hyperbola whose foci are at (0,±6) and the length of whose conjugate axis is 2√11.
The equation of the hyperbola whose transverse axis is 14 and whose vertex bisects the distance between centre and the focus is