Question

The equation of the hyperbola whose centre is (5, 2), vertex is (9, 2) and the length of conjugate axis is 6 is

• A. $\frac{(x-5{)}^2}{16}-\frac{(y-2{)}^2}{9}=-1$
• B. $\frac{(x-2{)}^2}{5}-\frac{(y-2{)}^2}{9}=1$
• C. $\frac{(x+2{)}^2}{7}-\frac{(y+2{)}^2}{9}=1$
• D. $\frac{(x-2{)}^2}{17}+\frac{(y-2{)}^2}{19}=1$

Answer 1

The correct option is C

$\frac{(x+2{)}^2}{7}-\frac{(y+2{)}^2}{9}=1$

$CA=a\Rightarrow a=4andb=3\therefore Hyperbolais\frac{(x-5{)}^2}{16}-\frac{(y-2{)}^2}{9}=1$