The equation of the line AB is y = x. If A and B lie on the same side of the line mirror 2x – y = 1, then the equation of the image of AB is
7x – y = 6
The required line is the line passing through the intersection of two lines and the image of the point on the line y = x and mirror 2x – y = 1.
∴ Given lines intersect at (1, 1)
Image of (0, 0) in the line mirror 2x – y = 1 is given by
x−02 =y−0−1 =−2(2x0−0−0−1)4+1⇒x=45, y=−25
∴ Required line passes through (1,1) and (45,−25). So its equation is
y-1 = −25−145−1(x−1)⇒7x−y=6