The equation of the line making 37- with x-axis and passing through 2-4 is -Hint- tan37-34-

From the question, slope of the line is m=tan37^∘=34 Equation of the line is given as y y_1=m(x x_1) ⇒ y ( 4)=34(x 2) ⇒ 4(y+4)=3(x 2) ⇒ 4y 3x+22=0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Physics

Introduction

The equation ...

Question

The equation of the line making $37^{\circ}$ with $x - a x i s$ and passing through $(2, - 4)$ is
[Hint:- $tan 37^{\circ} = \frac{3}{4}$ ]

4 y + 3 x + 22 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 y - 4 x + 22 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 y - 3 x + 22 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 y - 3 x - 22 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4 y - 3 x + 22 = 0$
From the question, slope of the line is $m = tan 37^{\circ} = \frac{3}{4}$
Equation of the line is given as $y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (- 4) = \frac{3}{4} (x - 2)$
$\Rightarrow 4 (y + 4) = 3 (x - 2)$
$\Rightarrow 4 y - 3 x + 22 = 0$

Suggest Corrections

Similar questions

Q. The equation of the line making

53^{\circ}

with positive

x - a x i s

and passing through

(2, 4)

is
[Hint:-

tan 53^{\circ} = \frac{4}{3}

]

Q. The equation of the line making

53^{\circ}

with positive

x - a x i s

and passing through

(2, 4)

is
[Hint:-

tan 53^{\circ} = \frac{4}{3}

]

Q. What is the equation of line passing through (0, 1) and making an angle with the y-axis equal to the inclination of the line x - y = 4 with x-axis ?

Q. The equation of the straight line which passes through the point

(2, - 3)

and makes an angle of

\frac{π}{4}

with the axis of

x

Q. The equation of the straight line passing through

(3, - 4)

and parallel to

x -

axis is

Join BYJU'S Learning Program

The equation of the line making 37∘ with x−axis and passing through (2,−4) is [Hint:- tan37∘=34]

The correct option is C 4y−3x+22=0From the question, slope of the line is m=tan37∘=34 Equation of the line is given as y−y1=m(x−x1) ⇒ y−(−4)=34(x−2) ⇒ 4(y+4)=3(x−2) ⇒ 4y−3x+22=0

The equation of the line making $37^{\circ}$ with $x - a x i s$ and passing through $(2, - 4)$ is
[Hint:- $tan 37^{\circ} = \frac{3}{4}$ ]

The correct option is C $4 y - 3 x + 22 = 0$
From the question, slope of the line is $m = tan 37^{\circ} = \frac{3}{4}$
Equation of the line is given as $y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (- 4) = \frac{3}{4} (x - 2)$
$\Rightarrow 4 (y + 4) = 3 (x - 2)$
$\Rightarrow 4 y - 3 x + 22 = 0$