The equation of the line making $53^{\circ}$ with positive $x - a x i s$ and passing through $(2, 4)$ is
[Hint:- $tan 53^{\circ} = \frac{4}{3}$ ]

3 y - 4 x - 4 = 0

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3 y - 2 x + 20 = 0

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y - 2 x + 20 = 0

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3 y - 2 x + 10 = 0

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Solution

The correct option is A $3 y - 4 x - 4 = 0$
From the question, slope of the line is $m = tan 53^{\circ} = \frac{4}{3}$
Equation of the line is given as $y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (4) = \frac{4}{3} (x - 2)$
$\Rightarrow 3 (y - 4) = 4 (x - 2)$
$\Rightarrow 3 y - 4 x - 4 = 0$

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Similar questions

Q. The equation of the line making

53^{\circ}

with positive

x - a x i s

and passing through

(2, 4)

is
[Hint:-

tan 53^{\circ} = \frac{4}{3}

]

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The equation of the line making 53∘ with positive x−axis and passing through (2,4) is [Hint:- tan53∘=43]

The correct option is A 3y−4x−4=0From the question, slope of the line is m=tan53∘=43 Equation of the line is given as y−y1=m(x−x1) ⇒ y−(4)=43(x−2) ⇒ 3(y−4)=4(x−2) ⇒ 3y−4x−4=0

The equation of the line making $53^{\circ}$ with positive $x - a x i s$ and passing through $(2, 4)$ is
[Hint:- $tan 53^{\circ} = \frac{4}{3}$ ]

The correct option is A $3 y - 4 x - 4 = 0$
From the question, slope of the line is $m = tan 53^{\circ} = \frac{4}{3}$
Equation of the line is given as $y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (4) = \frac{4}{3} (x - 2)$
$\Rightarrow 3 (y - 4) = 4 (x - 2)$
$\Rightarrow 3 y - 4 x - 4 = 0$