Question

The equation of the line parallel to $3x-2y+7=0$ and making an intercept $-4$ on $X$-axis is

• A. $3x-2y+12=0$
• B. $3x-2y-12=0$
• C. $3x+2y-12=0$
• D. $-3x+2y-12=0$

Answer 1

Answer: (A), (D)

$3x-2y+12=0$
$-3x+2y-12=0$

The equation of the line parallel $3x-2y+7=0$ is $3x-2y+c=0$ ...........(i) when $c$ is a constant.

Now this line makes an intercept $-4$ on $X$-axis.

$\therefore$ the point of intersection with $X$-axis is $(-4,0)$

So, line (i) passes through $(-4,0)$.

We substitute $x=-4$ and $y=0$ in equation (i) to get

$3\times (-4)-2\times 0+c=0$

$\Rightarrow c=12$

Substituting $c=12$ in equation (i), we have the required equation of the line as $3x-2y+12=0$.