Solving Simultaneous Linear Equation Using Cramer's Rule
The equation ...
Question
The equation of the line passing through (2,−1) and parallel to 3x+4y=10 is
A
3x+4y+2=0
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B
3x−4y−2=0
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C
3x+4y−2=0
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D
3x−4y+2=0
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Solution
The correct option is C3x+4y−2=0 The equation of a line parallel to another line ax+by=c......(i) is ax+by=k.......(ii)
If the line (ii) passes through a point P(p,q), then k can be evaluated by putting x=p and y=q in (ii). Given the equation of line: 3x+4y=10 A line parallel to the given line be: 3x+4y=k This line passes through (2,−1) Thus, 3(2)+4(−1)=k ⇒k=6−4 ⇒k=2 Hence, the required line is: 3x+4y=2.