The equation of the line passing through the origin and the point $(- 3, 5)$ is

5 x - 3 y = 0

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3 x - 5 y = 0

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5 x + 3 y = 0

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3 x + 5 y = 0

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Solution

The correct option is B $5 x + 3 y = 0$
The equation of a line passing through two points $P (x_{1}, y_{1})$ and $Q (x_{2}, y_{2})$ is given by,
$\frac{y - y_{1}}{y_{2} - y_{1}} = \frac{x - x_{1}}{x_{2} - x_{1}}$
The line passing through origin $= (0, 0)$ and $(- 3, 5)$ will be:
$\frac{x - 0}{- 3 - 0} = \frac{y - 0}{5 - 0}$
$\Rightarrow 5 x = - 3 y$
$\Rightarrow 5 x + 3 y = 0$
Hence, option C is correct.

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Similar questions

Q. The equation of the line passing through (1, 5) and perpendicular to the line 3x − 5y + 7 = 0 is
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(d) 5x + 3y + 7 = 0

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and perpendicular to the line

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The equation of the line passing through the origin and the point (−3,5) is

The correct option is B 5x+3y=0The equation of a line passing through two points P(x1,y1) and Q(x2,y2) is given by, y−y1y2−y1=x−x1x2−x1The line passing through origin =(0,0) and (−3,5) will be:x−0−3−0=y−05−0⇒5x=−3y⇒5x+3y=0Hence, option C is correct.

The equation of the line passing through the origin and the point $(- 3, 5)$ is