The equation of the line passing through the point $(1, 1)$ and parallel to the line $2 x - 3 y + 2 = 0$ is

x - 3 y = 1

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3 x - 2 y = 1

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2 x - 3 y + 1 = 0

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2 x - 3 y = 1

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Solution

The correct option is C $2 x - 3 y + 1 = 0$
The point is $(1, 1)$

The equation is $2 x - 3 y + 2 = 0$

The equation parallel to $2 x - 3 y + 2 = 0$ is $2 x - 3 y + k = 0$

$(1, 1)$ lies on the line

$⟹ 2 (1) - 3 (1) + k = 0$

$2 - 3 + k = 0$

$k = 1$

So the equation is $2 x - 3 y + 1 = 0$

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The equation of the line passing through the point (1,1) and parallel to the line 2x−3y+2=0 is

The correct option is C 2x−3y+1=0The point is (1,1)The equation is 2x−3y+2=0The equation parallel to 2x−3y+2=0 is 2x−3y+k=0(1,1) lies on the line⟹2(1)−3(1)+k=02−3+k=0k=1So the equation is 2x−3y+1=0

The equation of the line passing through the point $(1, 1)$ and parallel to the line $2 x - 3 y + 2 = 0$ is

The correct option is C $2 x - 3 y + 1 = 0$
The point is $(1, 1)$

The equation is $2 x - 3 y + 2 = 0$

The equation parallel to $2 x - 3 y + 2 = 0$ is $2 x - 3 y + k = 0$

$(1, 1)$ lies on the line

$⟹ 2 (1) - 3 (1) + k = 0$

$2 - 3 + k = 0$

$k = 1$

So the equation is $2 x - 3 y + 1 = 0$