The equation of the line passing through the point $(- 2, 3)$ and parallel to $3 x - 4 y + 7 = 0$ is

3 x + 4 y + 18 = 0

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3 x + 4 y - 18 = 0

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3 x - 4 y + 18 = 0

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3 x - 4 y - 18 = 0

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Solution

The correct option is B $3 x - 4 y + 18 = 0$
$P = (- 2, 3)$
$3 x - 4 y + 7 = 0$
$m = \frac{- 3}{- 4} = \frac{3}{4}$
Line: $y - 3 = \frac{3}{4} (x + 2)$
$4 (y - 3) = 3 x + 6$
$4 y - 12 = 3 x + 6$
$3 x - 4 y + 18 = 0$

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