The equation of the line passing through the point (c,d) and parallel to the line ax+by+c=0, is
A
a(x+c)+b(y+d)=0
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B
a(x+c)−b(y+d)=0
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C
a(x−c)+b(y−d)=0
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D
a(x−c)−b(y−d)=0
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Solution
The correct option is Ca(x−c)+b(y−d)=0 ax+by+c=0 So, the equation of the line which is parallel to the given line ax+by+λ=0 It passes through (c,d) is ac+bd+λ=0⇒λ=−(ac+bd) Now, the required equation of line ax+by−(ac+bd)=0∴a(x−c)+b(y−d)=0