wiz-icon
MyQuestionIcon
MyQuestionIcon
976
You visited us 976 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the line passing through the point (c,d) and parallel to the line ax+by+c=0, is

A
a(x+c)+b(y+d)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a(x+c)b(y+d)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a(xc)+b(yd)=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a(xc)b(yd)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C a(xc)+b(yd)=0
ax+by+c=0
So, the equation of the line which is parallel to the given line
ax+by+λ=0
It passes through (c,d) is
ac+bd+λ=0λ=(ac+bd)
Now, the required equation of line
ax+by(ac+bd)=0a(xc)+b(yd)=0

flag
Suggest Corrections
thumbs-up
17
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon