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Question

The equation of the line passing through the point of intersection of the line 4x−3y−1=0 and 5x−2y−3=0 and parallel to the line 2x−3y+2=0 is .

A
x3y=1
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B
3x2y=1
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C
7x7y1=0
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D
2x3y=1
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Solution

The correct option is C 7x7y1=0
Let equation of any straight line passing through the point of untersection of two given straight line be

k(4x3y1)=(5x2y3)=0
=>(4k+5)x(3k+2)y(k+3)=0(i)
xx
If the straight be parallel to the straight to the straight line 2x3y+2=0
4k+52=3k22
=>8k+6k=4+10
=>k=3
inserting the value of k in equation (i)
=>(4×(3)+5)x(3(3)+2)(4+3=0)

7x+7y+1=0
7x7y1=0

This line is the equation of the required straight line

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