The equation of the line passing through the point of intersection of the line 4x−3y−1=0 and 5x−2y−3=0 and parallel to the line 2x−3y+2=0 is .
A
x−3y=1
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B
3x−2y=1
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C
7x−7y−1=0
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D
2x−3y=1
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Solution
The correct option is C7x−7y−1=0
Let equation of any straight line passing through the point of untersection of two given straight line be
k(4x−3y−1)=(5x−2y−3)=0
=>(4k+5)x−(3k+2)y−(k+3)=0−−−−−−−−−−−−−−−(i)
xx
If the straight be parallel to the straight to the straight line 2x−3y+2=0
4k+52=−3k−2−2
=>−8k+6k=−4+10
=>k=3
inserting the value of k in equation (i)
=>(4×(−3)+5)x−(3(−3)+2)−(−4+3=0)
−7x+7y+1=0
7x−7y−1=0
This line is the equation of the required straight line