The equation of the line passing through the point of intersection of the lines 2x+y=5 and y=3x−5, and which is at the minimum distance from the point (1,2) is
A
x+y=3
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B
x−y=1
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C
x−2y=0
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D
2x+5y=7
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Solution
The correct option is Bx+y=3 2x+y=5→(1) 3x−y=5→(2) from 1 & 2, x=2,y=1 The line at a minimum distance from (1,2) and passing through (2,1) will be the line passing through the two points. ∴ equation of line is y−1=(1−22−1)(x−2) y+x=3