The equation of the line(s) passing through the point $(- 3, 5)$ is

x = - 3

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y = - 3

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x = 5

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y = 5

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Solution

The correct options are
A $x = - 3$
D $y = 5$
$A l i n e p a r a l l e l t o t h e X - a x i s i n t e r s e c t s t h e Y - a x i s a t t h e p o i n t P (0, c) . I f t h e l i n e p a s s e s t h r o u g h Q (p, q) t h e n, o b v i o u s l y, c = q . T a k e t h e l i n e a s y = m x + c . . . . . . . (i) w h e n m = t a n θ, θ b e i n g t h e a n g l e m a d e b y t h e l i n e w i t h t h e p o s i t i v e d i r e c t i o n o f X - a x i s & c = Y - i n t e r c e p t o f t h e l i n e . S i n c e (i) i s p a r a l l e l t o t h e X = a x i s θ = 0^{o} ⟹ t a n θ = 0 ⟹ m = 0.$
$T h u s, t h e e q u a t i o n o f l i n e w i l l b e y = q$
So, for a line parallel to x - axis and passing through (-3, 5). The equation will be:
y = 5

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The equation of the line(s) passing through the point (−3,5) is

The equation of the line(s) passing through the point $(- 3, 5)$ is