wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the line, when the portion of it intercepted between the axes is divided by the point (2,3) in the ratio of 3:2, is

A
Either x+y=4 or 9x+y=12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Either x+y=5 or 4x+9y=30
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Either x+y=4 or x+9y=12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Either x+y=5 or 9x+4y=30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D Either x+y=5 or 4x+9y=30
Now 2a5=2a=5

3b5=3b=5

Therefore equation of the line is x5+y5=1x+y=5.

Now 3a5=2a=103

2b5=3b=152

Therefore equation of the line is x10/3+y15/2=1.

3x10+2y15=1

9x+4y=30

Hence the equation of the line is x+y=5 or 9x+4y=30.


855005_926197_ans_1f69b996ee544942b7dbab2ba479f442.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Condition for Concurrency of Three Lines
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon