The equation of the line which is perpendicular to $x + 4 y - 5 = 0$ at it's $y$ intercept

16 x + 4 y - 5 = 0

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16 x - 4 y - 5 = 0

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16 x + 4 y + 5 = 0

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16 x - 4 y + 5 = 0

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Solution

The correct option is D $16 x - 4 y + 5 = 0$
$y$ intercept of the given line will be $\frac{5}{4}$
slope of the perpendicular line will be $4$
So, the required equation is
$y = 4 x + \frac{5}{4} \Rightarrow 16 x - 4 y + 5 = 0$

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