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Question

The equation of the line which makes an angle of 150 with the positive X-axis and cuts an intercept of length 4 on the negative Y-axis is

A
(31)x(3+1)y4=0
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B
(23)xy4=0
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C
(2+3)xy4=0
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D
(2+3)x+y+4=0
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Solution

The correct option is A (31)x(3+1)y4=0
Given data :
θ=15 and Intercept =4
C=4

Slope of line =tanθ m=tan15o

m=313+1

Equation of line in slope
Intercept form =y1=mx+c

y=(313+1)x4

(3+1)y=(31)x4

(31)x(3+1)y4=0

The equation of the line is (31)x(3+1)y1=0

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