The equation of the lines through $(- 1, - 1)$ and making an angle $45^{o}$ with the line $x + y = 0$ are

x + 1 = 0, x - y = 0

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x - y = 0, y + 1 = 0

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x + y + 2 = 0, y + 1 = 0

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x + 1 = 0, y + 1 = 0

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Solution

The correct option is B $x + 1 = 0, y + 1 = 0$
$\begin{matrix} L e t e q u a t i o n o f l i n e, y = m x + c A . T . Q, tan 45^{0} = \frac{m + 1}{1 - m} 1 - m = m + 1 m = 0 S o, e q u a t i o n o f l i n e, x + 1 = 0 y + 1 = 0 H e n c e, o p t i o n D i s c o r r e c t a n s w e r . \end{matrix}$

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